Principle:
Silver nitrate reacts with
sodium chloride and forms a white precipitate of silver chloride

When all the chloride ions
are precipitated as AgCl, excess of AgNO3 reacts with potassium
chromate indicator and forms a reddish brown precipitate of silver chromate.

Procedure:
1. Weigh accurately about 1.5
g. of NaCl (Equivalent weight = 58.46) transfer to a 250 ml volumetric flask.
2. Dissolve with a little
quantity of distilled water and make up the volume with distilled water to the
mark. Mix the solution thoroughly.
3. Fill the burette with the
given silver nitrate solution.
4. Pipette out exactly 25 ml of
the NaCl solution into a 250 ml conical flask.
5. Add few drops of potassium
chromate (5% aqueous solution) and mix the content of the flask.
6. Run down the AgNO3
solution from the burette into the conical flask in small quantities till the
reddish brown precipitate begins to appear, which is the end point.
7. Repeat the above experiment
till concordant titration values are obtained.
8. Carryout a blank with 25 ml
of distilled water and same quantity of K2Cr2O4
to get reddish brown colour when titrated with AgNO3.
9. Deduct the blank reading
with previous reading obtained for NaCl solution.
Calculation:
Volume of NaCl pipetted out = V1 ml
Normality of NaCl (by calculation) = N1
Volume of AgNO3 = V2 ml
V1 X N1

V2
Result: The strength of the given
AgNO3 solution = _____ N
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